Decoding the Chemical Clues
When a chemistry problem presents you with a set of specific properties, it's like a puzzle waiting to be solved. In this question, we are looking for a compound of lead that satisfies three distinct conditions: it must be a strong oxidising agent, it must be amphoteric, and it must be a component of lead storage batteries.
Let's break down these clues one by one to identify the mystery compound.
The Inert Pair Effect and Oxidising Power
Lead (Pb) is a heavy metal located in Group 14 of the periodic table. Elements in this group typically exhibit +2 and +4 oxidation states. However, as we move down the group, the +2 oxidation state becomes increasingly stable compared to the +4 state. This phenomenon is known as the inert pair effect, where the outermost s-electrons are reluctant to participate in bonding.
Because Pb2+ is much more stable than Pb4+, any compound containing lead in the +4 oxidation state will have a strong tendency to gain two electrons and reduce to the +2 state.
This spontaneous reduction (ΔG∘<0) makes Pb(IV) compounds excellent oxidising agents. Looking at our options, PbO2 contains lead in the +4 state, making it a prime candidate.
The Lead Storage Battery
Next, let's consider the practical application mentioned: the lead storage battery. This is the standard rechargeable battery used in automobiles.
In a fully charged lead storage battery:
- The anode is made of spongy lead (Pb).
- The cathode consists of a lead grid packed with lead dioxide (PbO2).
During discharge, both electrodes react with sulfuric acid to form lead sulfate (PbSO4). The presence of PbO2 at the cathode perfectly aligns with our second clue.
Verifying the Amphoteric Nature
Finally, we must confirm that PbO2 is amphoteric, meaning it can react with both acids and bases.
When
PbO2 reacts with a strong acid like hydrochloric acid, it acts as a base (and an oxidising agent):
PbO2+4HCl→PbCl2+Cl2+2H2O
Conversely, when it reacts with a strong base like sodium hydroxide, it acts as an acidic oxide, forming a soluble plumbate salt:
PbO2+2NaOH→Na2PbO3+H2O
Since PbO2 satisfies all three conditions—it is a strong oxidising agent, it is amphoteric, and it is used in lead storage batteries—we can confidently conclude that Compound A is lead dioxide (PbO2).