Analyzing the Setup
Imagine a chemical tug-of-war between two components, X and Y. The reaction is given as X⇌Y. The ultimate judge of who wins this tug-of-war is the standard Gibbs free energy change, ΔrG∘.
The relationship between ΔrG∘ and the major component is straightforward but crucial:
- If ΔrG∘<0, the forward reaction is spontaneous. The system naturally wants to convert X into Y, making Y the major component.
- If ΔrG∘>0, the forward reaction is non-spontaneous (meaning the backward reaction is spontaneous). The system prefers to stay as X, making X the major component.
The Master Equation
We are provided with a beautiful linear equation that dictates how ΔrG∘ changes with temperature T:
Our mission is to test the temperature given in each option, calculate the corresponding ΔrG∘, and see if the predicted major component matches the option's claim.
Evaluating the Options
Let's test Option (a): T=280 K
Substituting T=280 into our master equation:
ΔrG∘=120−83(280)=120−105=15 kJ mol−1
Since 15>0, the reaction is non-spontaneous in the forward direction, meaning X is the major component. However, Option (a) claims Y is major. So, Option (a) is incorrect.
Let's test Option (b): T=350 K
Substituting T=350:
ΔrG∘=120−83(350)=120−131.25=−11.25 kJ mol−1
Since −11.25<0, the reaction is spontaneous, making Y the major component. Option (b) claims X is major, which is incorrect.
Let's test Option (c): T=315 K
Substituting T=315:
ΔrG∘=120−83(315)=120−118.125=1.875 kJ mol−1
Since 1.875>0, the reaction is non-spontaneous, meaning X is the major component. Option (c) correctly states that X is major at this temperature! This is our winner.
Let's test Option (d): T=300 K
Just to be absolutely certain, let's check the last option. Substituting T=300:
ΔrG∘=120−83(300)=120−112.5=7.5 kJ mol−1
Since 7.5>0, X should be the major component. Option (d) claims Y is major, so it is incorrect.
The Equilibrium Point
As a bonus thought experiment, what happens when the tug-of-war is perfectly tied? This occurs when ΔrG∘=0.
120−83T=0⟹83T=120⟹T=320 K
At exactly 320 K, the system is in standard equilibrium. For any temperature below 320 K, ΔrG∘ is positive, and X dominates. For any temperature above 320 K, ΔrG∘ becomes negative, and Y takes over. This elegant linear relationship perfectly maps out the thermodynamic landscape of the reaction!