LEVELJEE Main
Visualized Solution
The Sigma Insight: Motion of a Charge in Magnetic Fields
The Setup
A Dance of Charges and Fields
Imagine you are a tiny, positively charged particle, zooming through space.
Suddenly, you enter a region filled with a uniform magnetic field.
But you don't just enter any which way—you dive in perfectly perpendicular to the magnetic field lines.
What happens next is one of the most elegant dances in physics.
The Lorentz Force
When a charged particle moves through a magnetic field, it experiences a force.
But this isn't just a simple push or pull.
This is the Lorentz force, and it has a very specific, almost quirky rule: it always acts perpendicular to both your velocity and the magnetic field.
Mathematically, we write this as:
Because of this cross product, the force doesn't push you forward to speed you up, nor does it pull you backward to slow you down.
Instead, it pushes you sideways.
The Master Equation
Work and Energy
Now, let's ask a crucial question: Does this magnetic force do any work on you?
In physics, work is defined as the dot product of force and displacement:
Since the magnetic force is always perpendicular to your direction of motion (your displacement), the angle between them is exactly .
And what is the cosine of ? It's zero!
The magnetic field does absolutely zero work on the charged particle.
The Conservation of Speed
Why is this so important?
Enter the Work-Energy Theorem, which states that the net work done on an object equals its change in kinetic energy:
Since , it immediately follows that .
Your kinetic energy is perfectly conserved.
And since kinetic energy is given by , your speed must also remain absolutely constant.
You don't speed up, and you don't slow down.
The Twist
Momentum and Direction
If your speed is constant, you might be tempted to think your momentum is constant too.
But here is where many students fall into a classic trap!
Kinetic energy is a scalar quantity.
It only cares about the magnitude of your velocity (your speed).
Momentum, however, is a vector quantity.
It cares about both your speed and your direction:
Because the magnetic force is constantly pushing you sideways, it forces you into a circular path.
You are constantly turning.
Even though your speedometer reads a constant number, your compass is spinning wildly!
Final Conclusion
Since your direction of motion is continuously changing, your velocity vector is changing.
And if your velocity vector is changing, your momentum vector must also be changing.
So, we arrive at our beautiful, counter-intuitive conclusion:
The kinetic energy of the particle remains perfectly constant because the magnetic force does no work.
However, the momentum of the particle is constantly changing because the magnetic force continuously alters the direction of motion.
Similar Questions
LEVELJEE Main
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected along the direction of the fields with a certain velocity, then
(A)
its velocity will decrease
(B)
its velocity will increase
(C)
it will turn towards right of direction of motion
(D)
it will turn towards left of direction of motion
LEVELJEE Main
If an electron and a proton having same momenta enter perpendicularly to a magnetic field, then
(A)
curved path of electron and proton will be same (ignoring the sense of revolution)
(B)
they will move undeflected
(C)
curved path of electron is more curved than that of proton
(D)
path of proton is more curved
JEE Advanced 2011
LEVELJEE Main
An electron and a proton are moving on straight parallel paths with same velocity. They enter a semi-infinite region of uniform magnetic field perpendicular to the velocity. Which of the following statement(s) is/are true?
* Multiple Correct Options
(A)
They will never come out of the magnetic field region
(B)
They will come out travelling along parallel paths
(C)
They will come out at the same time
(D)
They will come out at different times
JEE Main 2002
LEVELJEE Main
The time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of its
(A)
speed
(B)
mass
(C)
charge
(D)
magnetic induction
JEE Advanced 1999
LEVELJEE Main
A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a
(A)
straight line
(B)
circle
(C)
helix
(D)
cycloid
LEVELJEE Advanced
A particle of charge and mass moving under the influence of a uniform electric field and uniform magnetic field follows a trajectory from to as shown in figure. The velocities at and are and . Which of the following statement(s) is/are correct ?
* Multiple Correct Options
(A)
(B)
Rate of work done by the electric field at is
(C)
Rate of work done by the electric field at is zero
(D)
Rate of work done by both the fields at is zero
JEE Main 2007
LEVELJEE Advanced
A charged particle with charge enters a region of constant, uniform and mutually orthogonal fields and with a velocity perpendicular to both and and comes out without any change in magnitude or direction of . Then,
(A)
(B)
(C)
(D)
LEVELJEE Main
Two particles and of masses and respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are and , respectively and the trajectories are as shown in the figure. Then
(A)
(B)
(C)
and
(D)
and
LEVELJEE Main
In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a
(A)
helix
(B)
straight line
(C)
ellipse
(D)
circle
LEVELJEE Main
A particle of mass and charge moving with velocity describes a circular path of radius when subjected to a uniform transverse magnetic field of induction . The work done by the field when the particle completes one full circle is
(A)
(B)
zero
(C)
(D)
