Animated Solution for Physics - Thermodynamics: Calculate the value of mean free path (λ) for oxygen molecules at temperature 27∘C and pressure 1.01×105 Pa. Assume the molecular diameter 0.3 nm and the gas is ideal. (kB=1.38×10−23 JK−1)
Select Answer:
Visualized Solution
Visualizing Mean Free Path
Mean free path (λ) is the average distance a molecule travels between collisions.
It depends on the collision cross-section (πd2) and number density.
The Formula
λ=2πd2pkBT
Where:
kB=Boltzmann constant
T=Absolute temperature
d=Molecular diameter
p=Pressure
Extracting Given Data
p=1.01×105 Pa
T=27∘C=27+273=300 K
d=0.3 nm=0.3×10−9 m
kB=1.38×10−23 J/K
Substitution
λ=2×3.14×(0.3×10−9)2×1.01×1051.38×10−23×300
Simplifying the Expression
Numerator: 1.38×300×10−23=414×10−23
Denominator: 1.414×3.14×0.09×10−18×1.01×105
≈4.03×10−13
Final Calculation
λ=4.03×10−13414×10−23
λ≈102.7×10−10 m
λ≈102×10−9 m
Final Answer
λ=102 nm
Correct Option is (d)
The Way Forward
Notice that λ∝pT
If temperature doubles at constant pressure, λ doubles.
If pressure doubles at constant temperature, λ halves.
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The Sigma Insight: Kinetic Theory of Gases
Solution Diagram
The Chaos of the Microscopic World
Imagine you are shrunk down to the size of an oxygen molecule, trapped inside a container. It is absolute chaos. You are zipping around at hundreds of meters per second, but you can't go very far before—BAM!—you collide with another molecule. The average distance you manage to travel in a straight line between these violent collisions is what physicists call the mean free path (λ).
In this problem, we are tasked with finding exactly how far an oxygen molecule travels between collisions at a pleasant room temperature of 27∘C and standard atmospheric pressure.
The Master Equation
To find the mean free path, we rely on a beautiful result from the Kinetic Theory of Gases:
λ=2πd2pkBT
Let's break down why this formula makes perfect physical sense:
- Temperature (T) is in the numerator: Higher temperature means molecules are moving faster and the gas tends to expand (if not rigidly confined), increasing the space between molecules.
- Pressure (p) is in the denominator: Higher pressure means the molecules are packed more densely. More crowding equals more frequent collisions, hence a shorter path.
- Diameter squared (d2) is in the denominator: The larger the molecule, the bigger its "target area" (πd2). A bigger target means it's much harder to avoid hitting others.
- The 2 factor: This accounts for the fact that all molecules are moving, not just the one we are tracking. It represents the relative velocity between colliding particles.
Setting Up the Raw Data
Before we plug numbers into our master equation, we must ensure absolute harmony in our units. Physics is unforgiving when it comes to mixed units!
- Pressure:p=1.01×105 Pa (Already in standard SI units).
- Temperature:T=27∘C. We must convert this to absolute temperature (Kelvin).
T=27+273=300 K
- Diameter:d=0.3 nm. We convert this to meters.
d=0.3×10−9 m
- Boltzmann Constant:kB=1.38×10−23 J/K.
Executing the Calculation
Now, we carefully substitute our pristine data into the formula:
λ=2×π×(0.3×10−9)2×1.01×1051.38×10−23×300
Let's tackle the numerator first. It's straightforward:
1.38×300×10−23=414×10−23
Next, the denominator. We must square the diameter first:
(0.3×10−9)2=0.09×10−18
Now, multiply the constants in the denominator (2≈1.414, π≈3.14):
1.414×3.14×0.09×10−18×1.01×105≈4.03×10−13
Finally, we divide the numerator by our simplified denominator:
λ=4.03×10−13414×10−23≈102.7×10−10 m
The Final Verdict
To match our options, we convert the result back into nanometers (1 nm=10−9 m):
λ≈102.7×10−10 m=10.27×10−9 m≈102 nm
The mean free path is approximately 102 nm. This means an oxygen molecule travels about 340 times its own diameter before crashing into a neighbor. The microscopic world is indeed a crowded, chaotic place!