Sigma Percentile
LEVELJEE Advanced

Animated Solution for Chemistry - Chemical Thermodynamics: If the bond dissociation energies of , and (all diatomic molecules) are in the ratio of and for the formation of is . The bond dissociation energy of will be

Select Answer:

Visualized Solution

The Sigma Insight: Enthalpy and Hess's Law

Solution Diagram
Imagine you are in a molecular laboratory, tasked with synthesizing exactly one mole of the diatomic gas . To do this, you must start with the elemental building blocks in their standard states: and gases.

The Setup

Visualizing the Reaction
The standard enthalpy of formation, denoted as , is strictly defined for the creation of one mole of a substance. Therefore, our balanced chemical equation must reflect this constraint:
This fractional stoichiometry is crucial. If you were to write , you would be calculating the enthalpy for two moles, which is a classic trap that leads to silly mistakes!

The Master Equation

Hess's Law
To find the enthalpy change of this reaction, we rely on Hess's Law, specifically using bond dissociation energies. The logic is beautifully simple: we must invest energy to break the bonds of the reactants (an endothermic process), and the system will release energy when the new bonds of the products are formed (an exothermic process).
Substituting our specific molecules into this master equation, we get:

The Algebraic Substitution

The problem provides a fascinating ratio for the bond dissociation energies of , , and , which is . To make our algebra elegant, let's introduce a variable to represent the bond energy of .
Let This implies And
We are also given that the standard enthalpy of formation is . Let's substitute all these values into our equation:

The Final Reveal

Now, we just need to carefully solve for . Let's simplify the terms inside the bracket:
Combining the positive terms gives us . Subtracting from this yields:
To isolate , we divide both sides by :
Since we defined the bond dissociation energy of as , we have our final answer:
Looking at the given options—, , and —our calculated value of is nowhere to be found. Therefore, the correct choice is confidently None of these. This problem is a brilliant test of your fundamental understanding of standard states and your ability to trust your algebraic execution!

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