Sigma Percentile
LEVELJEE Main

Animated Solution for Physics - Oscillations: A body executes simple harmonic motion. The potential energy (PE), the kinetic energy (KE) and total energy (TE) are measured as function of displacement . Which of the following statements is true?

Select Answer:

Visualized Solution

Visualizing Energy in SHM

  • Let's analyze the energy of a particle executing Simple Harmonic Motion (SHM).
  • The displacement varies from to , where is the amplitude.

Energy Formulas

  • Potential Energy:
  • Kinetic Energy:
  • Total Energy:

Analyzing the Mean Position

  • At the mean position, the displacement is zero.
  • Substitute into the energy equations.

Evaluating Energies at

  • Potential Energy: (Minimum)
  • Kinetic Energy: (Maximum)

Conclusion

  • The Kinetic Energy (KE) is maximum when the particle is at the mean position ().

The Way Forward

  • At extreme positions ():
  • (Minimum)
  • (Maximum)

The Sigma Insight: Force and Energy Method in SHM

Solution Diagram

The Dance of Energy in Simple Harmonic Motion

Imagine you are sitting on a swing. As you pump your legs and soar through the air, you are experiencing one of the most beautiful phenomena in physics: Simple Harmonic Motion (SHM). But what is really happening behind the scenes? It is a continuous, elegant dance between two forms of energy—Kinetic and Potential.
In any SHM system, whether it's a pendulum, a mass on a spring, or a swing, the total mechanical energy remains absolutely constant. This is the law of conservation of energy. However, the distribution of this energy changes depending on where the object is in its path.

The Master Equations

Let's look at the mathematical heartbeat of this system. If a particle of mass is oscillating with an angular frequency and an amplitude , its displacement from the center (the mean position) is given by .
The Potential Energy (PE), which is the energy stored due to the object's position, is given by:
The Kinetic Energy (KE), which is the energy of motion, depends on the object's velocity. Expressed in terms of displacement, it is:
Notice how these two equations are perfectly complementary. If you add them together, the terms cancel out, leaving the Total Energy (TE):
This Total Energy is a constant value, completely independent of .

Analyzing the Mean Position

Now, let's focus on the exact center of the oscillation—the mean position. Here, the displacement .
What happens to our energies at this specific point? Let's substitute into our Potential Energy equation:
The Potential Energy drops to zero. All the stored energy has been released. But where did it go? It transformed entirely into Kinetic Energy. Let's verify this by substituting into the Kinetic Energy equation:
Look at that! The Kinetic Energy is now equal to the Total Energy. Because the term being subtracted () is at its absolute minimum (zero), the Kinetic Energy is at its absolute maximum.

The Physical Intuition

Does this make physical sense? Absolutely. Think back to the swing. When are you moving the fastest? Right at the bottom of the arc, as you rush past the center point. At this mean position, your velocity is maximum, and therefore, your Kinetic Energy is maximum.
Conversely, when you reach the highest point of your swing (the extreme position where ), you momentarily stop. Your velocity is zero, meaning your Kinetic Energy is zero. At that exact moment, all your energy is stored as Potential Energy, ready to pull you back down.
Therefore, the statement "KE is maximum when " is the correct physical and mathematical reality of Simple Harmonic Motion.

Similar Questions

LEVELBoard

In a simple harmonic oscillator, at the mean position

(A)
kinetic energy is minimum, potential energy is maximum
(B)
both kinetic and potential energies are maximum
(C)
kinetic energy is maximum, potential energy is minimum
(D)
both kinetic and potential energies are minimum
JEE Main 2021
LEVELJEE Main

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal?

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

A particle is executing simple harmonic motion (SHM) of amplitude , along the X-axis, about . when its potential energy (PE) equals kinetic energy (KE), the position of the particle will be

(A)
(B)
(C)
(D)
JEE Advanced (1989)
LEVELJEE Main

A linear harmonic oscillator of force constant and amplitude has a total mechanical energy of . Its (a) maximum potential energy is (b) maximum kinetic energy is (c) maximum potential energy is (d) minimum potential energy is zero

* Multiple Correct Options
(A)
maximum potential energy is
(B)
maximum kinetic energy is
(C)
maximum potential energy is
(D)
minimum potential energy is zero
JEE Advanced 2003
LEVELJEE Main

For a particle executing SHM the displacement is given by . Identify the graph which represents the variation of potential energy (PE) as a function of time and displacement .

(A)
I, III
(B)
II, IV
(C)
II, III
(D)
I, IV
JEE Main 2004
LEVELBoard

The total energy of a particle, executing simple harmonic motion is where, is the displacement from the mean position.

(A)
(B)
(C)
independent of
(D)
JEE Main 2006
LEVELJEE Main

Starting from the origin, a body oscillates simple harmonically with a period of . After what time will its kinetic energy be of the total energy?

(A)
(B)
(C)
(D)
JEE Main 2015
LEVELJEE Main

For a simple pendulum, a graph is plotted between its Kinetic Energy (KE) and Potential Energy (PE) against its displacement (d) Which one of the following represents these correctly? (graphs are schematic and not drawn to scale)

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

A particle starts executing simple harmonic motion (SHM) of amplitude and total energy . At any instant, its kinetic energy is , then its displacement is given by

(A)
(B)
(C)
(D)