Animated Solution for Mathematics - Differential Equations: At present, a firm is manufacturing 2000 items. It is estimated that the rate of change of production P w.r.t. additional number of workers x is given by dxdP=100−12x. If the firm employs 25 more workers, then the new level of production of items is
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Visualized Solution
Initial Production State
Current production: P=2000 items
Additional workers: x=0
The Rate of Change
Given rate: dxdP=100−12x
Goal: Find P when x=25
Separating Variables
Rearrange terms: dP=(100−12x1/2)dx
Integrating the Rate
Integrate both sides:
∫dP=∫(100−12x1/2)dx
Performing Integration
P=100x−123/2x3/2+C
Simplifying the Equation
P=100x−8x3/2+C
Finding the Constant C
Use initial condition:
At x=0, P=2000
Evaluating C
2000=100(0)−8(0)3/2+C
⟹C=2000
The Specific Production Function
P(x)=100x−8x3/2+2000
Substituting x=25
For x=25:
P=100(25)−8(25)3/2+2000
Calculating the Exponent
253/2=(25)3=53=125
Final Arithmetic
P=2500−8(125)+2000
P=2500−1000+2000
Final Production Level
P=1500+2000=3500 items
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The Sigma Insight: Variable Separable Method
Solution Diagram
Analyzing the Setup
Imagine you are standing on the floor of a bustling manufacturing plant. The firm is currently churning out 2000 items, and we are tasked with modeling the production growth as new workers are added.
The problem provides the rate of change of production P with respect to the number of workers x:
dxdP=100−12x
In engineering terms, this is the 'marginal production.' It represents the instantaneous rate at which production increases for every infinitesimal addition of labor.
The Integration Journey
To determine the total production P, we must accumulate these marginal gains. We begin by separating the variables:
dP=(100−12x1/2)dx
Next, we integrate both sides of the equation:
∫dP=∫(100−12x1/2)dx
Applying the power rule for integration, the integral of 100 is 100x. For the term 12x1/2, we increase the exponent to 3/2 and divide by the new exponent:
P=100x−12(3/2x3/2)+C
Simplifying the expression, we obtain the general production function:
P=100x−8x3/2+C
The Constant of Reality
The constant C represents the 'base production'—the initial output of 2000 items before any new workers are hired. We use the initial condition where x=0 and P=2000:
2000=100(0)−8(0)3/2+C
This calculation confirms that C=2000. Our specific production function is therefore:
P(x)=100x−8x3/2+2000
The Final Calculation
To find the production level after hiring 25 new workers, we substitute x=25 into our function:
P=100(25)−8(25)3/2+2000
Since 253/2=(25)3=53=125, the equation becomes:
P=2500−8(125)+2000
Calculating the terms, we find P=2500−1000+2000. The final production total is: