Sigma Percentile
LEVELJEE Main

Animated Solution for Physics - Magnetic Effects of Current: An ionized gas contains both positive and negative ions. If it is subjected simultaneously to an electric field along the +x-direction and a magnetic field along the +z-direction, then

Select Answer:

Visualized Solution

Coordinate System and Fields

  • Electric field:
  • Magnetic field:

Ionized Gas

  • Gas contains positive ions () and negative ions ().

Effect of Electric Field

  • Electric force:
  • Velocity of positive ion:
  • Velocity of negative ion:

Magnetic Lorentz Force

  • Magnetic force:

Deflection of Positive Ion

  • Deflects towards direction.

Deflection of Negative Ion

  • Deflects towards direction.

Conclusion

  • Both positive and negative ions deflect towards the direction.

The Sigma Insight: Motion of a Charge in Magnetic Fields

Solution Diagram
Have you ever wondered what happens when you subject a chaotic, ionized gas to both an electric and a magnetic field simultaneously? It sounds like a recipe for absolute pandemonium. You might expect the positive and negative ions to scatter in completely opposite directions, tearing the gas apart.
But physics has a beautiful way of surprising us with hidden symmetries. Let's dive into this classic problem and uncover the elegant dance of charges in crossed fields.

Setting the Stage

The Crossed Fields
Imagine a region of space where we have set up two uniform fields. We have an electric field pointing straight along the positive x-direction, and a magnetic field pointing straight up along the positive z-direction.
Mathematically, we can write these as:
Into this arena, we introduce an ionized gas. This gas is a soup of positively charged ions () and negatively charged ions (). Initially, let's assume they are just milling about. What happens the moment we turn on the fields?

The Electric Push

The electric field is the first to act. It's the brute force of the electromagnetic world. It doesn't care if you are moving or standing still; if you have a charge, it will push you.
For the positive ions, the electric force pushes them in the direction of the field. They accelerate and gain a velocity along the positive x-axis:
For the negative ions, the story is reversed. The electric force pushes them against the field. They accelerate and gain a velocity along the negative x-axis:
So far, everything is intuitive. The positive and negative ions are moving in exactly opposite directions.

The Magnetic Twist

Now comes the twist. As soon as these ions start moving, they awaken the sleeping giant: the magnetic field. The magnetic Lorentz force only acts on moving charges, and its direction is governed by the cross product:
Let's analyze the positive ion first. It's moving along and the magnetic field is along .
Using our right-hand rule, or the cyclic property of unit vectors, we know that .
The positive ion is deflected towards the negative y-direction.

The Beautiful Cancellation

Now, what about the negative ion? It has a negative charge, and it's moving in the negative x-direction. Let's plug it into the Lorentz force equation:
Look closely at the math. We have a negative sign from the charge, and a negative sign from the velocity. When we multiply them, the two negatives cancel out perfectly!
The negative ion is also deflected towards the negative y-direction!

The Grand Conclusion

This is the profound beauty of the Lorentz force. Because the negative ion has both an opposite charge AND an opposite velocity compared to the positive ion, the two "opposites" cancel out in the cross product.
The result? The entire ionized gas—both positive and negative ions—is swept together in the exact same direction, deflecting towards the axis. It's a stunning example of how mathematical structure dictates physical reality, turning expected chaos into synchronized motion.

Similar Questions

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A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected along the direction of the fields with a certain velocity, then

(A)
its velocity will decrease
(B)
its velocity will increase
(C)
it will turn towards right of direction of motion
(D)
it will turn towards left of direction of motion
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Two ions of masses 4 amu and 16 amu have charges +2e and +3e, respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then,

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(B)
lighter ion will be deflected more than heavier ion
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In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a

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A charged particle (electron or proton) is introduced at the origin () with a given initial velocity . A uniform electric field and a uniform magnetic field exist everywhere. The velocity , electric field and magnetic field are given in columns 1, 2 and 3, respectively. The quantities are positive in magnitude. $\begin{array}{lll} \hline \text{Column 1} & \text{Column 2} & \text{Column 3} \\ \hline \text{(I) Electron with } \mathbf{v} = 2\frac{E_0}{B_0}\hat{x} & \text{(i) } \mathbf{E} = E_0\hat{z} & \text{(P) } \mathbf{B} = -B_0\hat{x} \\ \text{(II) Electron with } \mathbf{v} = \frac{E_0}{B_0}\hat{y} & \text{(ii) } \mathbf{E} = -E_0\hat{y} & \text{(Q) } \mathbf{B} = B_0\hat{x} \\ \text{(III) Proton with } \mathbf{v} = 0 & \text{(iii) } \mathbf{E} = -E_0\hat{x} & \text{(R) } \mathbf{B} = B_0\hat{y} \\ \text{(IV) Proton with } \mathbf{v} = 2\frac{E_0}{B_0}\hat{x} & \text{(iv) } \mathbf{E} = E_0\hat{x} & \text{(S) } \mathbf{B} = B_0\hat{z} \\ \hline \end{array}$
Question 1:

In which case would the particle move in a straight line along the negative direction of Y-axis (i.e. move along )?

(A)
(IV) (ii) (S)
(B)
(II) (iii) (Q)
(C)
(III) (ii) (R)
(D)
(III) (ii) (P)
Question 2:

In which case will the particle move in a straight line with constant velocity?

(A)
(II) (iii) (S)
(B)
(III) (iii) (P)
(C)
(IV) (i) (S)
(D)
(III) (ii) (R)
Question 3:

In which case will the particle describe a helical path with axis along the positive z-direction?

(A)
(II) (ii) (R)
(B)
(III) (iii) (P)
(C)
(IV) (i) (S)
(D)
(IV) (ii) (R)
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(A)
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(B)
circle
(C)
helix
(D)
cycloid
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An electron and a proton are moving on straight parallel paths with same velocity. They enter a semi-infinite region of uniform magnetic field perpendicular to the velocity. Which of the following statement(s) is/are true?

* Multiple Correct Options
(A)
They will never come out of the magnetic field region
(B)
They will come out travelling along parallel paths
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They will come out at the same time
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They will come out at different times
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An electron moving with a speed along the positive -axis at enters a region of uniform magnetic field which exists to the right of -axis. The electron exits from the region after sometime with the speed at coordinate , then

(A)
(B)
(C)
(D)
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, and all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity. The masses of , and are , and respectively. Then

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will be deflected most
(B)
will be deflected most
(C)
and will be deflected equally
(D)
all will be deflected equally
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An electron is moving along +x-direction with a velocity of . It enters a region of uniform electric field of pointing along +y-direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the x-direction will be

(A)
, along + z-direction
(B)
, along − z-direction
(C)
, along + z-direction
(D)
, along − z-direction
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If an electron and a proton having same momenta enter perpendicularly to a magnetic field, then

(A)
curved path of electron and proton will be same (ignoring the sense of revolution)
(B)
they will move undeflected
(C)
curved path of electron is more curved than that of proton
(D)
path of proton is more curved