Sigma Percentile
JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Chemical Kinetics: If the activation energy of a reaction is , the fraction of molecules at , having enough energy to react to form products is . The value of is ......... (Rounded off to the nearest integer) [Use, ].

Enter Numerical Value:

Visualized Solution

  • The fraction of molecules having kinetic energy greater than the activation energy is given by the Arrhenius factor.

The Sigma Insight: Theories of Chemical Reaction

Solution Diagram

The Dance of Molecules

Imagine a microscopic world inside a reaction vessel. Millions of gas molecules are constantly colliding, bouncing off each other in a chaotic dance. However, not every collision leads to a chemical reaction. For a reaction to occur, the colliding molecules must possess a certain minimum amount of kinetic energy, known as the activation energy ().
If we plot the kinetic energies of all these molecules, we get the famous Maxwell-Boltzmann distribution curve. Most molecules have an average, moderate energy. Only a tiny fraction of elite molecules sit at the far right tail of the curve, possessing energy greater than .

The Arrhenius Factor

Mathematically, this crucial fraction of molecules is given by the Arrhenius factor:
This elegant expression tells us exactly what portion of the total molecules is capable of reacting at a given absolute temperature . Our goal in this problem is to calculate this fraction and compare it to the given expression .

The Trap of Units

Before we plug in the numbers, we must be extremely careful with our units. This is a classic trap in physical chemistry! The activation energy is given as , but the universal gas constant is given in Joules ().
To ensure consistency, we must convert the activation energy into Joules by multiplying by :

The Final Calculation

Now, let's substitute our values into the exponent term :
First, we multiply the terms in the denominator:
Next, we perform the division:
So, the fraction of molecules is approximately . The problem states that this fraction is equal to . Therefore, by comparing the exponents, we get:
Finally, the question asks us to round off the value of to the nearest integer. Since is much closer to than to , we round it up.
Final Answer:

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