LEVELJEE Main
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The Sigma Insight: Bar Magnet and Magnetic Dipole
The Setup
A Needle in a Non-Uniform Field
Imagine a region of space where the magnetic field is not perfectly uniform. In a uniform field, the magnetic field lines are parallel and equally spaced, meaning the field strength is identical everywhere. However, in a non-uniform magnetic field, the field lines are curved and the spacing between them varies. This means the magnitude and direction of the magnetic field vector change from point to point.
Now, let's place a small magnetic needle into this environment. A magnetic needle is essentially a tiny bar magnet. In physics, we model this as a magnetic dipole consisting of a North pole with pole strength and a South pole with pole strength , separated by a small distance.
Analyzing the Forces
The Tug of War
When placed in a magnetic field, each pole of the needle experiences a magnetic force. The fundamental equation for the force on a magnetic pole is .
For the North pole, the force is , acting in the direction of the local magnetic field at that specific point. For the South pole, the force is , acting in the opposite direction of the local magnetic field at its respective location.
Translational Motion
Why the Net Force is Non-Zero
Here is where the non-uniformity of the field becomes crucial. Because the field is non-uniform, the magnetic field strength at the location of the North pole () is strictly different from the magnetic field strength at the location of the South pole ().
Mathematically, since $\vec{B}_N
eq \vec{B}_S$, it directly implies that the magnitudes of the forces are unequal: $|\vec{F}_N|
eq |\vec{F}_S|$.
When we calculate the net translational force on the needle, we sum these two forces:
Because the forces are unequal in magnitude (and potentially not perfectly anti-parallel), they do not cancel each other out. Therefore, $\vec{F}_{net}
eq 0$. The needle will experience a net force, causing it to accelerate translationally through space.
Rotational Motion
The Turning Effect
What about rotation? The two forces and are acting at two different points on the rigid body of the needle. Unless the needle is perfectly aligned along a straight field line (which is a highly specific and unstable equilibrium in a non-uniform field), the lines of action of these two forces will not coincide.
Whenever you have forces acting at different points with non-coinciding lines of action, they generate a turning effect, or torque. The net torque is given by:
Since the forces are unequal and misaligned, $\vec{\tau}_{net}
eq 0$. The needle will experience a net torque, causing it to rotate.
The Final Verdict
In conclusion, a magnetic needle placed in a non-uniform magnetic field will experience both a net force and a net torque. It will be pulled towards the region of stronger magnetic field while simultaneously rotating to align itself with the local field lines.
A quick tip for JEE: Always contrast this with a uniform magnetic field. In a perfectly uniform field, , so the forces are exactly equal and opposite, resulting in zero net force. However, it can still experience a torque if it is placed at an angle to the field!
Similar Questions
JEE Main 2021
LEVELJEE Advanced
A bar magnet of length 14 cm is placed in the magnetic meridian with its North pole pointing towards the geographic North pole. A neutral point is obtained at a distance of 18 cm from the centre of the magnet. If , then the magnetic moment of the magnet is ()
(A)
(B)
(C)
(D)
LEVELJEE Advanced
The length of a magnet is large compared to its width and breadth. The time period of its oscillation in a vibration magnetometer is . The magnet is cut along its length into three equal parts and three parts are then placed on each other with their like poles together. The time period of this combination will be
(A)
(B)
(C)
(D)
