Analyzing the Setup
Imagine you are standing on the coordinate plane, looking at a circle centered at (2,3) with a radius of 4. A line, x+y=3, slices through this circle, creating a chord PQ.
Two tangents are drawn to the circle at points P and Q, meeting at an external point S(α,β). We aim to find the value of 4α−7β.
The Secret Weapon
The Chord of Contact
The most powerful tool in our arsenal for this problem is the concept of the Chord of Contact. When you draw tangents to a circle from an external point S, the line connecting the points of tangency (P and Q) is defined by the equation T=0.
For a circle given by x2+y2+2gx+2fy+c=0, the equation of the chord of contact for a point S(x1,y1) is:
xx1+yy1+g(x+x1)+f(y+y1)+c=0
This formula acts as a shortcut, bypassing the need to calculate the specific coordinates of P and Q.
Expanding the Circle
Before applying the T=0 condition, we must express the circle in its general form. Starting with the standard equation:
Expanding this yields x2−4x+4+y2−6y+9=16. Simplifying, we arrive at the general form:
Substituting the point S(α,β) into the T=0 formula, we obtain:
The Dance of Coefficients
Rearranging this equation into the standard linear form Ax+By+C=0, we get:
x(α−2)+y(β−3)−(2α+3β+3)=0
This represents the line PQ. Since the problem defines the line PQ as x+y−3=0, these two equations must be proportional. We set up the following ratios:
Solving the System
From the first two ratios, we have α−2=β−3, which simplifies to:
Equating the first and third ratios, we have α−2=32α+3β+3. Cross-multiplying by 3 yields:
Substituting α=β−1 into α−3β=9, we get (β−1)−3β=9, which leads to −2β=10, or β=−5. Consequently, α=−6.
Final Calculation
We have determined the coordinates of point S to be (−6,−5). The final step is to calculate the value of 4α−7β:
The final result is 11.