Sigma Percentile
JEE Main 2003
LEVELJEE Main

Animated Solution for Chemistry - Basic Concepts in Chemistry: 25 mL of a solution of barium hydroxide on titration with 0.1 molar solution of hydrochloric acid gave a titre value of 35 mL. The molarity of barium hydroxide solution was

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Visualized Solution

  • Let the molarity of be .
  • Volume of ,
  • Molarity of ,
  • Volume of ,

  • At the equivalence point, the number of equivalents of acid equals the number of equivalents of base.

  • Normality () is related to Molarity () by the n-factor ().
  • For , (since it provides 2 ions).
  • For , (since it provides 1 ion).

  • Substituting the values into the equivalence equation:

  • Simplifying the equation:

  • Calculating the final value:

\text{What if } H_2SO_4 \text{ was used?}

  • If was used instead of , its n-factor would be 2.
  • The equation would become:

The Sigma Insight: Stoichiometric and Volumetric Calculations

Solution Diagram
Welcome to the fascinating world of volumetric analysis! Today, we are stepping into the shoes of an analytical chemist to solve a classic titration puzzle. Titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.

Analyzing the Setup

Imagine you are in the chemistry lab. We have a conical flask containing of an unknown concentration of barium hydroxide, . Above it, a burette is filled with hydrochloric acid, . We slowly add the acid drop by drop until the indicator changes color, signaling that the reaction is complete. This happens exactly when of acid has been added. This volume is known as the 'titre value'.

The Master Equation

At the exact moment of neutralization, the law of equivalence states that the number of equivalents of the acid must perfectly match the number of equivalents of the base. This gives us our master equation:
Here, represents Normality and represents Volume. But wait, the problem gives us Molarity (), not Normality. How do we bridge this gap?
Normality is simply the n-factor () multiplied by Molarity:
The n-factor is a crucial concept. For an acid, it's the number of replaceable ions (basicity). For a base, it's the number of replaceable ions (acidity).
For barium hydroxide, , it dissociates to give two hydroxide ions, so its n-factor is . For hydrochloric acid, , it gives one proton, so its n-factor is .

Final Calculation

Let's carefully substitute these values into our equivalence equation.
For the base (left side):
For the acid (right side):
Plugging it all together:
Now, it's just simple algebra. Two times twenty-five gives us fifty on the left. On the right, zero point one times thirty-five is three point five.
Dividing by , we get our final answer:
The molarity of the barium hydroxide solution is exactly . A beautiful and clean result that perfectly demonstrates the power of the law of equivalence!

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