Boiling Point Elevation
The Power of Ions
Imagine you are standing in a kitchen, boiling a pot of pure water. You know it boils at exactly 373.15 K (or 100∘C). But what happens when you toss in a handful of a mysterious electrolyte, say A2B3? The water suddenly needs more heat to boil! This phenomenon is known as Boiling Point Elevation, and it is a classic colligative property.
In this problem, we are given a 1 molal aqueous solution of A2B3. The catch? It is only 60% ionized. Let's break down how this partial ionization affects the boiling point.
Analyzing the Setup
First, we need to understand the master equation for boiling point elevation:
Here, ΔTb is the elevation in boiling point, i is the van't Hoff factor, Kb is the molal elevation constant (0.52 K kg mol−1 for water), and m is the molality (1 molal). The only missing piece of the puzzle is the van't Hoff factor, i.
The Master Equation for van't Hoff Factor
To find i, we must look at how A2B3 behaves in water. When it dissolves, it dissociates into its constituent ions:
From one molecule of A2B3, we get 2 ions of A+3 and 3 ions of B−2. This means the total number of ions produced upon complete dissociation, n, is 2+3=5.
However, the problem states that the electrolyte is only 60% ionized. This means the degree of dissociation, α, is 0.6. We can relate i, n, and α using the formula:
Substituting our values:
So, our effective number of particles per formula unit in the solution is 3.4.
Final Calculation
Now that we have the van't Hoff factor, we can easily calculate the elevation in boiling point:
This means the boiling point of the water has increased by 1.768 K. To find the final boiling point of the solution, Tb, we add this elevation to the boiling point of pure water:
Tb=373.15+1.768=374.918 K
The question asks us to round off to the nearest integer. Rounding 374.918 gives us our final answer:
Final Answer: 375
This problem beautifully illustrates how the microscopic behavior of ions directly impacts the macroscopic physical properties of a solution. Always remember to account for the degree of dissociation when dealing with weak or partially ionized electrolytes!