Mean Deviation

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JEE Main 2011

LEVELJEE Main

If the mean deviation about the median of the numbers a, 2a,.......,50a is 50, then | a| equals

If the mean deviation of the numbers 1, 1 + d, 1 + 2d, .... 1 + 100d from their mean is 255, then d is equal to:

JEE Main 2022 (25 July Shift 2)

LEVELJEE Main

If the mean deviation about median for the number 3, 5, 7, 2k, 12, 16, 21, 24 arranged in the ascending order, is 6 then the median is

JEE Main 2024 (04 Apr Shift 1)

LEVELJEE Main

Let $α, β \in R$ . Let the mean and the variance of 6 observations $- 3, 4, 7, - 6, α, β$ be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is :

(A)

\frac{13}{3}

(B)

\frac{16}{3}

(C)

\frac{11}{3}

(D)

\frac{14}{3}

JEE Main 2025 April

LEVELJEE Main

Let the mean and the standard deviation of the observation 2, 3, 3, 4, 5, 7, a, b be 4 and $2$ respectively. Then the mean deviation about the mode of these observations is :

(A)

(B)

\frac{3}{4}

(C)

(D)

\frac{1}{2}

JEE Advanced 2023

LEVELJEE Main

Consider the given data with frequency distribution $x_{i}$ : 3, 8, 11, 10, 5, 4 $f_{i}$ : 5, 2, 3, 2, 4, 4 Match each entry in List-I to the correct entries in List-II.

List-I

(P)

(P) The mean of the above data is

(Q)

(Q) The median of the above data is

(R)

(R) The mean deviation about the mean of the above data is

(S)

(S) The mean deviation about the median of the above data is

List-II

If the mean deviation about the median of the numbers a, 2a,.......,50a is 50, then | a| equals

If the mean deviation of the numbers 1, 1 + d, 1 + 2d, .... 1 + 100d from their mean is 255, then d is equal to:

If the mean deviation about median for the number 3, 5, 7, 2k, 12, 16, 21, 24 arranged in the ascending order, is 6 then the median is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Let α,β∈R. Let the mean and the variance of 6 observations −3,4,7,−6,α,β be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is :

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Consider the given data with frequency distribution xi​: 3, 8, 11, 10, 5, 4 fi​: 5, 2, 3, 2, 4, 4 Match each entry in List-I to the correct entries in List-II.

List-I

List-II

Let $α, β \in R$ . Let the mean and the variance of 6 observations $- 3, 4, 7, - 6, α, β$ be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is :

Consider the given data with frequency distribution $x_{i}$ : 3, 8, 11, 10, 5, 4 $f_{i}$ : 5, 2, 3, 2, 4, 4 Match each entry in List-I to the correct entries in List-II.