Group 18 Elements

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JEE Advanced 2026

LEVELJEE Advanced

Correct statement(s) about the compounds P, Q and R is(are) $Xe (g) + F_{2} (g) 873 K, 7 bar P$ (1 : 5 ratio) $P + O_{2} F_{2} 143 K Q + O_{2}$ $Q + H_{2} O complete hydrolysis R + HF$

* Multiple Correct Options

(A)

P has two lone pairs of electrons on the central atom.

(B)

Q has a perfect octahedral geometry.

(C)

Q can act as a fluorinating agent.

(D)

The molecular structure of R is trigonal pyramidal.

JEE Main 2026

LEVELJEE Advanced

Reaction of $P t F_{6}$ with oxygen ( $O_{2}$ ) gas results in the formation of an ionic compound, $X^{+} Y^{-}$ . Correct statement(s) is (are)

* Multiple Correct Options

(A)

The bond order of

X^{+}

is 1.5.

(B)

Valence d-orbitals of the metal ion in

X^{+} Y^{-}

has 5 electrons.

(C)

P t F_{6}

acts as an oxidant in this reaction.

(D)

P t F_{6}

acts as a fluorinating agent in this reaction.

JEE Advanced 2022

LEVELJEE Advanced

The reaction of Xe and $O_{2} F_{2}$ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is _______.

JEE Advanced 2014

LEVELJEE Advanced

Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme shown below is

At $143 K$ , the reaction of $XeF_{4}$ with $O_{2} F_{2}$ produces a xenon compound $Y$ . The total number of lone pair(s) of electrons present on the whole molecule of $Y$ is _______.

JEE Main 2021

LEVELJEE Main

A xenon compound 'A' upon partial hydrolysis gives $XeO_{2} F_{2}$ . The number of lone pair of electrons present in compound A is ......... (Round off to the nearest integer).

JEE Main 2021

LEVELJEE Main

Match List-I with List-II. \begin{array}{ll} \text{List-I (Species)} & \text{List-II (Number of lone pair of electrons on the central atom)} \\ \text{A. } XeF_2 & 1.\ 0 \\ \text{B. } XeO_2F_2 & 2.\ 1 \\ \text{C. } XeO_3F_2 & 3.\ 2 \\ \text{D. } XeF_4 & 4.\ 3 \end{array} Choose the most appropriate answer from the options given below :

The type of hybridisation and number of lone pair(s) of electrons of Xe in $XeOF_{4}$ , respectively, are

(A)

sp^{3} d^{2}

and 1

(B)

sp^{3} d

and 2

(C)

sp^{3} d

and 1

(D)

sp^{3} d^{2}

and 2

JEE Main 2020

LEVELJEE Advanced

The shape/structure of $[XeF_{5}]^{-}$ and $XeO_{3} F_{2}$ , respectively, are

(A)

pentagonal planar and trigonal bipyramidal

(B)

octahedral and square pyramidal

(C)

trigonal bipyramidal and pentagonal planar

(D)

trigonal bipyramidal and trigonal bipyramidal

LEVELJEE Main

Which one of the following reaction of xenon compounds is not feasible?

(A)

XeO_{3} + 6 HF ⟶ XeF_{6} + 3 H_{2} O

(B)

3 XeF_{4} + 6 H_{2} O ⟶ 2 Xe + XeO_{3} + 12 HF + 1.5 O_{2}

(C)

2 XeF_{2} + 2 H_{2} O ⟶ 2 Xe + 4 HF + O_{2}

(D)

XeF_{6} + RbF ⟶ Rb [XeF_{7}]

JEE Main 2019

LEVELBoard

The noble gas that does not occur in the atmosphere is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Correct statement(s) about the compounds P, Q and R is(are) Xe (g)+F2​(g)873 K, 7 bar​P (1 : 5 ratio) P+O2​F2​143 K​Q+O2​ Q+H2​Ocomplete hydrolysis​R+HF

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Reaction of PtF6​ with oxygen (O2​) gas results in the formation of an ionic compound, X+Y−. Correct statement(s) is (are)

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The reaction of Xe and O2​F2​ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is _______.

Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme shown below is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } At 143 K, the reaction of XeF4​ with O2​F2​ produces a xenon compound Y. The total number of lone pair(s) of electrons present on the whole molecule of Y is _______.

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } A xenon compound 'A' upon partial hydrolysis gives XeO2​F2​. The number of lone pair of electrons present in compound A is ......... (Round off to the nearest integer).

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The type of hybridisation and number of lone pair(s) of electrons of Xe in XeOF4​, respectively, are

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The shape/structure of [XeF5​]− and XeO3​F2​, respectively, are

Which one of the following reaction of xenon compounds is not feasible?

The noble gas that does not occur in the atmosphere is

Correct statement(s) about the compounds P, Q and R is(are) $Xe (g) + F_{2} (g) 873 K, 7 bar P$ (1 : 5 ratio) $P + O_{2} F_{2} 143 K Q + O_{2}$ $Q + H_{2} O complete hydrolysis R + HF$

Reaction of $P t F_{6}$ with oxygen ( $O_{2}$ ) gas results in the formation of an ionic compound, $X^{+} Y^{-}$ . Correct statement(s) is (are)

The reaction of Xe and $O_{2} F_{2}$ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is _______.

At $143 K$ , the reaction of $XeF_{4}$ with $O_{2} F_{2}$ produces a xenon compound $Y$ . The total number of lone pair(s) of electrons present on the whole molecule of $Y$ is _______.

A xenon compound 'A' upon partial hydrolysis gives $XeO_{2} F_{2}$ . The number of lone pair of electrons present in compound A is ......... (Round off to the nearest integer).

The type of hybridisation and number of lone pair(s) of electrons of Xe in $XeOF_{4}$ , respectively, are

The shape/structure of $[XeF_{5}]^{-}$ and $XeO_{3} F_{2}$ , respectively, are